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[Forensic 19]
2진수를 문자열로 변경을 해보자.
string = """
0100111001010110010000110101010001000110010001000101
0110001000000100101101000110001000000100101001001100
0100010101011010010001010101001001001011010100100100
1010001000000101001001000101010101010010000001001011
0100011001010101010100100101000000100000010110100100
1010001000000101001000100000010110000100011001000110
0101010100100000010101010101001001010000001000000101
0010010001010101010100100000010100100100110001001011
0101100101000010010101100101000000100000010110100100
1010001000000100011101000011010100100101101001010101
0101010001001011010101110101101001001010010011010101
0110010010010101000001011001010100100100100101010101"""
string = string.replace('\n','')
hex_string = str(hex(int(string, 2)))[2:]
bytes_object = bytes.fromhex(hex_string)
print(bytes_object)
아직은 어떤 말인지 모르겠다.. 일단 기본적인 시저암호라 생각하고 돌려보자.
string = """
0100111001010110010000110101010001000110010001000101
0110001000000100101101000110001000000100101001001100
0100010101011010010001010101001001001011010100100100
1010001000000101001001000101010101010010000001001011
0100011001010101010100100101000000100000010110100100
1010001000000101001000100000010110000100011001000110
0101010100100000010101010101001001010000001000000101
0010010001010101010100100000010100100100110001001011
0101100101000010010101100101000000100000010110100100
1010001000000100011101000011010100100101101001010101
0101010001001011010101110101101001001010010011010101
0110010010010101000001011001010100100100100101010101"""
string = string.replace('\n','')
hex_string = str(hex(int(string, 2)))[2:]
bytes_object = bytes.fromhex(hex_string)
for i in range(26) :
for word in bytes_object:
if(word >= ord('A') and word <= ord('Z')):
if(word+i >= ord('A') and word+i <= ord('Z')):
print(chr(word+i), end='')
else :
print(chr(ord('A')-1+(word+i-ord('Z'))), end='')
else :
print(chr(word),end='')
print()
기본 문자열에서 +9 하면 AuthKey가 나온다.
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